The electric field strength depends only on the x and y coordinates according to the law 
= a(x 
+ y 
)/ (x 2 + y 2 ), where a is a constant, 
and 
are the unit vectors of the x and y axes. Find the flux of the vector 
through a sphere of radius R with its center at the origin of coordinates. Using the above result, also calculate total charge enclosed by the sphere.
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
φ φ = 4πRa , Q = 4πRa ∈ 0
Sol. Given, 
= 
Let 
= 
ds;
where ds = magnitude of small area considered on surface of sphere.
and 
= unit vector along the radius
So 
= R
Now flux of 
= 
φ φ = 
• 
ds
φ φ = 
ds = 
φ φ = 4 πR 2 . 
= 4πRa
and φ φ = 
∴ Q = φ φ∈ 0 = 4πRa ∈ 0
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems