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CGP EDU Academic Team
Published on: September 12, 2026
The magnitude of a given vector with end points (4, – 4, 0) and (– 2, – 2, 0) must be
Text Solution
Verified by ExpertsThe correct answer is:
D
\vec{r} = \vec{r}_2 - \vec{r}_1 = (-2\hat{i} - 2\hat{j} + 0\hat{k}) - (4\hat{i} - 4\hat{j} + 0\hat{k})
\(\Rightarrow \vec{r} = -6\hat{i} + 2\hat{j} + 0\hat{k}\)
\(\therefore |\vec{r}| = \sqrt{(-6)^2 + (2)^2 + 0^2}\)
\(= \sqrt{36 + 4} = \sqrt{40} = 2 \sqrt{10}\)
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