If a particle of mass m is moving with constant velocity v parallel to x-axis in x-y plane as shown in fig. Its angular momentum with respect to origin at any time t will be
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We know that, Angular momentum
\(\vec{L} = \vec{r} \times \vec{p}\) in terms of component becomes
\(\vec{L} = \begin{vmatrix} \hat{i} & \hat{j} & \hat{k} \\ x & y & z \\ p_x & p_y & p_z \end{vmatrix}\)
As motion is in x-y plane (z = 0 and P_z = 0 ), so \(\vec{L} = \vec{k} \left( x p_y - y p_x \right)\)
Here x = vt, y = b, \(\mathbf{p}_x = mv\) and p_y = 0
\(\vec{L} = \vec{k} [vt \times 0 - bmv] = -mvb\vec{k}\)
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