The position of a particle is given by \vec{r} = (\hat{i} + 2\hat{j} - \hat{k}) and momentum \vec{p} = (3\hat{i} + 4\hat{j} - 2\hat{k}) . The angular momentum is perpendicular to the
Text Solution
Verified by ExpertsA
Неге , \vec{r} = \hat{i} + 2\hat{j} - \hat{k}, \vec{p} = 3\hat{i} + 4\hat{j} - 2\hat{k}
\(\vec{L} = \vec{r} \times \vec{p} = \begin{vmatrix} \hat{i} & \hat{j} & \hat{k} \\ 1 & 2 & -1 \\ 3 & 4 & -2 \end{vmatrix} = \hat{i}(-4 + 4) + \hat{j}(-3 + 2) + \hat{k}(4 - 6) = 0\hat{i}\)
-1\hat{j} - 2\hat{k}
\vec{L} has component along -y axis and -z axis but it has no component along the x axis. The angular momentum \vec{L} is in yz-plane. i.e., perpendicular to x-axis.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems