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CGP EDU Academic Team
Published on: September 12, 2026
P, Q and R are three coplanar forces acting at a point and are in equilibrium. Given P = 1.9318 kg wt, \(\sin \theta_1 =\) 0.9659, the value of R is ( in kg wt)
Text Solution
Verified by ExpertsThe correct answer is:
C
\(\frac{P}{\sin \theta_1} = \frac{Q}{\sin \theta_2} = \frac{R}{\sin 150^\circ}\)
\(\Rightarrow \frac{1.93}{\sin \theta_1} = \frac{R}{\sin 150^\circ}\)
\(\Rightarrow R = \frac{1.93 \times \sin 150^\circ}{\sin \theta_1} = \frac{1.93 \times 0.5}{0.9659} = 1\)
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