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CGP EDU Academic Team
Published on: September 12, 2026
\vec{A} = 2\hat{i} + 4\hat{j} + 4\hat{k} and \(\vec{\mathbf{B}} = 4\hat{i} + 2\hat{j} - 4\hat{k}\) are two vectors. The angle between them will be
Text Solution
Verified by ExpertsThe correct answer is:
D
\(\cos \theta = \frac{\vec{A} \cdot \vec{B}}{|\vec{A}| \cdot |\vec{B}|} = \frac{a_1 b_1 + a_2 b_2 + a_3 b_3}{|\vec{A}| \cdot |\vec{B}|}\)
\(= \frac{2 \times 4 + 4 \times 2 - 4 \times 4}{|\vec{A}| \cdot |\vec{B}|} = 0\)
\ \ \(\theta = \cos^{-1}(0)\) \(\Rightarrow \theta = 90^{\circ}\)
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