The relative density of material of a body is found by weighing it first in air and then in water. If the weight in air is (5.00 =0.005 ) Newton and weight in water is (4.00 = 0.05) Newton . Then the relative density along with the maximum permissible percentage error is
Text Solution
Verified by ExpertsA
Weight in air \((5.00 \times 0.05) N\)
Weight in water \((4.00 \cdot 0.05) N\)
Loss of weight in water \((1.00 \cdot 0.1) N\)
Now relative density \(= \frac{\text{weight in air}}{\text{weight loss in water}}\)
i.e. R . D \(\frac{5.00 \cdot 0.06}{1.00 \cdot 0.1}\)
Now relative density with max permissible error
\(= \frac{5.00}{1.00} \pm \left| \frac{0.05}{5.00} + \frac{0.1}{1.00} \right| \times 100\) \(= 5.0 \cdot (1 + 10)\%\) \(=5.0 \pm 1.1\%\)
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems