In an experiment, the following observation's were recorded : L = 2.820 m , M = 3.00 kg , l = 0.087 cm , Diameter D = 0.041 cm Taking g = 9.81 \(\pi r^5 2\) using the formula , Y = \(\frac{4.1 \mathrm{Mgi}}{x_0^{-1}}\) , the maximum permissible error in Y is
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\(y = \frac{4 M g L}{m D^2 I}\) so maximum permissible error in Y = \(\frac{.XP}{Y} \times 100 = \left| \frac{.SM}{M} + \frac{.9}{g} + \frac{.X}{l} + \frac{2.0}{p} + \frac{.N}{j} \right| \times 100\)
\(= \left| \frac{1}{300} + \frac{1}{981} + \frac{1}{2820} + 2 \times \frac{1}{41} + \frac{1}{87} \right| \times 100\) \(=0.065 \times 100 = 6.5\%\)
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