The length, breadth and thickness of a block are given by \(l \quad 12 \, \mathrm{cm},\quad b \quad 6 \, \mathrm{cm}\) and \(x \quad 2.45 \text{ cm}\)
The volume of the block according to the idea of significant figures should be
Text Solution
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Volume \(\mathbf{V} = l \wedge b \wedge t\)
\(=12 \times 6 \times 2.45\) \(=1764 \, \mathrm{cm}^3\)
V \(=1.764 \times 10^{3} \text{ cm}^{3}\)
since, the minimum number of significant figure is one in breadth, hence volume will also contain only one significant figure. Hence, \(V = 2 \times 10^3 \, \mathrm{cm}^3\) .
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