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CGP EDU Academic Team
Published on: September 12, 2026
The position of a particle moving in the xy -plane at any time t is given by x = (3t^2 - 6t) metres , y = t^2 - 2t metres . Select the correct statement about the moving particle from the following
Text Solution
Verified by ExpertsThe correct answer is:
C
\(v_x - \frac{dx}{dt} - \frac{d}{dt} (3t^2 - 6t) - 6t - 6\) . At \(\varepsilon \quad 1, \nu_{x} \quad 0\)
\(v_{!} - \frac{dy}{dt} - \frac{d}{dt} (t^2 - 2t) - 2t - 2\) . At \(\varepsilon \quad 1, v_y \quad 0\)
Hence \(v = \sqrt{v_x^2 + v_y^2} = 0\)
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