If a train travelling at 72 kmph is to be brought to rest i…

Physics Motion in a Straight Line Non-Uniform Motion Single Correct MCQ

Published on: September 12, 2026

If a train travelling at 72 kmph is to be brought to rest in a distance of 200 metres, then its retardation should be

20 \(\sqrt{72} = 6\sqrt{2}\)

10 \(\sqrt{72} = 6\sqrt{2}\)

2 \(\sqrt{72} = 6\sqrt{2}\)

1 \(\sqrt{72} \approx 8.5\)

Text Solution

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The correct answer is:

\(u \quad 72 \text{ kmph} \quad 20 \text{ m/s},\) \nu = 0

By using \(v^{c} \quad w^{2} \cdot 2 \pi s\) ⇒ ⇒ \(0 - \frac{U^{2}}{2.5}\) \(-\frac{(20)^2}{2 \times 200} - 1 \, \mathrm{m/s}^2\)

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