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CGP EDU Academic Team
Published on: September 12, 2026
The relation \(3t \sqrt{\overline{3x}} + 6\) describes the displacement of a particle in one direction where x^k is in metres and t in sec. The displacement, when velocity is zero, is
Text Solution
Verified by ExpertsThe correct answer is:
D
\(3x = \sqrt{3x - 6} , 3x = (3x - 6)^2\)
\(\Rightarrow x = 3t^{2} - 12t + 12\)
\(v - \frac{dx}{dt} - 6t + 12\) , for \(v_0, t = 2 \text{ sec}\)
x = 3(2)^2 - 12, -2 + 12 = 0
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