A car starts from rest and moves with uniform acceleration a on a straight road from time t = 0 to t = T . After that, a constant deceleration brings it to rest. In this process the average speed of the car is
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For First part,
u = 0, t = T and acceleration = a
\(\therefore v = 0 + \sigma T = \sigma T\) and \(s, -0 + \frac{1}{2} a \tau^{i} - \frac{1}{2} a \tau^{2}\)
For Second part,
\(\upsilon = \sigma \mathbf{T}.\) retardation= a 1 , \nu = 0 and time taken = T 1 (let)
\(\mathrm{H - O - H}\) \(0 \quad u \cdot a T_{1}\) \(\to \alpha^{T} \quad \alpha_{1} \Gamma_{1}\)
and from \nu^2 = u^2 - 2as_2 \(\Rightarrow S_2 = \frac{u^2}{2a_1} = \frac{1}{2} \frac{a^2 t^2}{a} .\)
\(S_z = -\frac{1}{2} \sigma T / T_1\) \(\left| As \ \alpha = \frac{\delta T}{T_1} \right|\)
. \(v_{x} = \frac{s_{1} + s_{2}}{T + T_{1}} = \frac{1}{2} a T^{2} + \frac{1}{2} a T \times T_{1}\)
\(= \frac{1}{2} \sigma T (T + T_1) \over T + T_1,\) \(-\frac{1}{2}\alpha T\)
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