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CGP EDU Academic Team
Published on: September 12, 2026
A particle moves along x- axis as x = 4(t - 2) + a(t - 2)^2 Which of the following is true ?
Text Solution
Verified by ExpertsThe correct answer is:
B
x = 4(t - 2) + a(t - 2)^2
At \(\varepsilon \quad 0,x \quad -8+4a \quad 4a-8\)
\(v - \frac{dx}{dt} - 4 + 2\alpha i t - 2\)
At \(\varepsilon \quad 0, \nu \quad 4 - 4 \alpha \quad 4(1 - \alpha)\)
But acceleration, \(0 - \frac{d^2 x}{dt^2} - 20\)
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