A body is released from the top of a tower of height h . It…

Physics Motion in a Straight Line Motion Under Gravity Single Correct MCQ

Published on: September 12, 2026

A body is released from the top of a tower of height h . It takes t sec to reach the ground. Where will be the ball after time t / Z sec

At \(\frac{h}{2}\) from the ground

At \hbar/4 from the ground

Depends upon mass and volume of the body

At 3t^{3/4} from the ground

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The correct answer is:

Let the body after time \(\frac{1}{2}\) be at x from the top, then

\(x - \frac{1}{2} g \frac{t^2}{4} - \frac{g t^2}{8}\) …(i)

\(h = \frac{1}{2} g t^2\) …(ii)

Eliminate t from (i) and (ii), we get \(x - \frac{h}{4}\)

. Height of the body from the ground \(-h - \frac{h}{4} - \frac{3h}{4}\)

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