A balloon starts rising from the ground with an acceleration of 1.25 m / s 2 after 8s, a stone is released from the balloon. The stone will ( g = 10 m / s 2 )
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When the stone is released from the balloon. Its height \(h - \frac{1}{2} a t^{2} - \frac{1}{2} \times 1.25 \times (8)^{2} = -40 m\) and velocity
\(v \quad at \quad 1.25 \, /8 \quad 10 \, m/s\)
Time taken by the stone to reach the ground
\(t = \frac{v}{g} \left| 1 + \sqrt{1 + \frac{2gh}{v^2}} \right| = \frac{10}{10} \left| 1 + \sqrt{1 + \frac{2 \times 10 \times 40}{(10)^2}} \right|\) =4 sec
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