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CGP EDU Academic Team
Published on: September 12, 2026
If a freely falling body travels in the last second a distance equal to the distance travelled by it in the first three second, the time of the travel is
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Verified by ExpertsThe correct answer is:
B
The distance traveled in last second.
\(S_{w1} - u + \frac{g}{2} (2t - 1)\) \(-\frac{1}{2} \times 9.8 (2t - 1)\) = 4.9(2r - 1)
and distance traveled in first three second,
\(S_{\text{max}} = 0 + \frac{1}{2} \times 9.8 \times 9 = 44.1 \, m\)
According to problem \(S_{\text{lacc}} \quad S_{\text{lines}}\)
, 4.9(2t - 1) = 4.1 , 2t - 1 = 9 ⇒ ⇒ t = 5 sec .
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