A parachutist after bailing out falls 50 m without friction. When parachute opens, it decelerates at 2 m/s 2 . He reaches the ground with a speed of 3 m / s . At what height, did he bail out ?
Text Solution
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After bailing out from point A parachutist falls freely under gravity. The velocity acquired by it will ‘ v ’
From 
= 980
[As u = 0, 
, s = 50 m ]
At point B , parachute opens and it moves with retardation of 2 
and reach at ground (Point C ) with velocity of 
For the part ‘ BC ’ by applying the equation 
, 
, 
, s = h
⇒ ⇒ 
⇒ ⇒ 
⇒ ⇒ 
m.
So, the total height by which parachutist bail out = 
= 293 m.
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