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CGP EDU Academic Team
Published on: September 12, 2026
If the equation for the displacement of a particle moving on a circular path is given by \(\langle r \rangle = 2t^{\frac{1}{2}} + 0.5\) , where \(\frac{d}{dt}\) is in radians and t in seconds, then the angular velocity of the particle after 2 sec from its start is
Text Solution
Verified by ExpertsThe correct answer is:
C
\(w = \frac{dv}{dt} - \frac{d}{dt}(2t + 0.5) - 6t^2\)
at t =2 s, \(\omega = 6 \times (2)^2 = 24 \, rads\)
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