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CGP EDU Academic Team
Published on: September 12, 2026
A particle covers 50 m distance when projected with an initial speed. On the same surface it will cover a distance, when projected with double the initial speed
Text Solution
Verified by ExpertsThe correct answer is:
C
\(R = \frac{u^2 \sin 2\theta}{g} = \frac{R}{u^2}.\) So if the speed of projection doubled, the range will becomes four times,
i.e. , \(4 \times 50 = 200 \text{ m}\)
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