An object is projected with a velocity of 20 m/s making an angle of 45 o with horizontal. The equation for the trajectory is h = Ax – Bx 2 where h is height, x is horizontal distance, A and B are constants. The ratio A : B is (g = 10 ms –2 )
Text Solution
Verified by ExpertsD
Standard equation of projectile motion
\(y - x \tan \nu - \frac{g x^2}{2 u^2 \cos^2 \nu}\)
Comparing with given equation
\(A = \tan \theta\) and \(g - \frac{g}{2u^{2} \cos^{2} \alpha}\)
So \(\frac{A}{g} - \frac{\tan r \wedge 2u^{2} \cos^{2} r}{g} - 40\)
(As \(\theta = 45, u = 20 \text{ m/s}, g = 10 \text{ m/s}^2\) )
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems