For a given velocity, a projectile has the same range R for two angles of projection if t 1 and t 2 are the times of flight in the two cases then
Text Solution
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For same range angle of projection should be q and 90– q
So, time of flights \(\ell = \frac{2v^2 \sin \theta \cos \theta}{g}\) and
\(t_2 = \frac{2u \sin \beta_0}{g} = \frac{2u \cos r}{g}\)
By multiplying \(= t t_{2} = \frac{4 u^{2} r^{2} \sin \theta \cos \theta}{g^{2}}\)
\(\varepsilon_{t_s} = - \frac{2 \left( u^o \sin 2u \right)}{g} - \frac{2R}{g}\) ⇒ ⇒ \(\Sigma_{1} \times \Sigma_{2} \times \mathbb{R}\)
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