Published by:
CGP EDU Academic Team
Published on: September 11, 2026
A tube of length l is filled completely with an incompressible liquid of mass \(\mathbf{M}\) and closed at both the ends. The tube is then rotated in a horizontal plane about one of its ends with a uniform angular velocity \((\omega)\) . The force exerted by the liquid at the other end is
Text Solution
Verified by ExpertsThe correct answer is:
A
\(\operatorname{cov} = \left| \frac{N}{I} : \alpha x \right|\)

force on ‘ dM ’ mass is
dF = (dM) r \ddot{x}
By integration we can get the force exerted by whole liquid
⇒ ⇒ \(F = \int_{b}^{c} \frac{M}{l} x \, dx\) \(-\frac{1}{2} M \omega^{2} L^{2}\)
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