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CGP EDU Academic Team
Published on: September 12, 2026
A particle moves in the x-y plane under the action of a force \vec{F} such that the value of its linear momentum \(\left(\vec{P}\right)\) at anytime t is \(P_{x} = 2 \cos t, p_{y} = 2 \sin t.\) The angle \(\theta\) between \vec{F} and \vec{p} at a given time t. will be
Text Solution
Verified by ExpertsThe correct answer is:
C
\(P_x = 2 \cos t\) , \(P_y = 2 \sin t\) \ \ \(\vec{P} = 2 \cos t \ \hat{i} + 2 \sin t \ \hat{j}\)
\(\vec{F} = \frac{d\vec{P}}{dt} = -2 \sin t \, \hat{i} + 2 \cos t \, \hat{j}\)
\(\vec{F} \cdot \vec{P} = 0\) \ \ \(\theta = 90^\circ\)
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