The radius of a sphere is (5.3 ± ± 0.1) cm . The percentage…

Physics Units, Dimensions and Measurement Errors of Measurement Single Correct MCQ

Published by: CGP EDU Academic Team

Published on: September 12, 2026

The radius of a sphere is (5.3 ± ± 0.1) cm . The percentage error in its volume is

\(\frac{0.1}{5.3} \times 100\)

\(3 \times \frac{0.1}{5.3} \div 100\)

\(\frac{0.1 \times 100}{3.53}\)

\(3 + \frac{0.1}{5.3} \times 100\)

Text Solution

Verified by Experts

The correct answer is:

\(\therefore V = \frac{4}{3} \pi r^{3}\)

\ \ % error in volume

= 3 : 4 error in radius.

\(-\frac{3 \times 0.1}{5.3} \times 100\)

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