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Physics Motion in a Straight Line Non-Uniform Motion Single Correct MCQ
Published on: September 12, 2026

A point moves with uniform acceleration and \nu_1, \nu_2 and \ell^{3} denote the average velocities in the three successive intervals of time \{\tau_1, \tau_2\} and \(\left[ ? \right]\) . Which of the following relations is correct

A
\(\{v_1 - v_2\} : \{v_2 - v_3\} \quad \{t_1 - t_2\} : \{t_2 + t_3\}\)
B
\(\{v_{1} - v_{2}\} : \{v_{2} - v_{3}\} \quad \{t_{1} + t_{2}\} : \{t_{2} + t_{3}\}\)
C
\(\{v_1 - v_2\} : \{v_2 - v_3\} \quad \{t_1 - t_2\} : \{t_1 - t_3\}\)
D
\(\{v_1 - v_2\} : \{v_2 - v_3\} \quad \{t_1 - t_2\} : \{t_2 - t_3\}\)

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Text Solution

Verified by Experts
The correct answer is:
B

Let \(\mathbf{U}_1, \mathbf{U}_2, \mathbf{U}_3\) and \Psi_4 be velocities at time \(\tau \quad 0, t_1, (t_1 + t_2)\) and \{t_1 + t_2 + t_3\} respectively and acceleration is a then \(v_1 - \frac{u_1 + u_2}{2}, v_2 - \frac{u_2 + u_3}{2} \text{ and } v_3 - \frac{u_3 + u_4}{2}\)

Also \(\mathbf{v}_2 \quad \mathbf{v}_1 + \alpha t_1, \quad \mathbf{v}_3 \quad \mathbf{v}_1 + \alpha (t \cdot + \epsilon_2)\)

and \(\mathbf{U}_4 \quad \mathbf{d}_1 + \alpha' \{ \mathbf{E}_1 + \mathbf{E}_2 + \mathbf{E}_3 \}\)

By solving, we get \(\frac{V_1 - V_2}{V_2 - V_3} = \frac{(t_1 + t_2)}{(t_2 + t_3)}\)

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