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CGP EDU Academic Team
Published on: September 12, 2026
The acceleration \(\cdot \hat{C}\) in m 15^\circ of a particle is given by \(\rho \quad 3x^{i} + 2t + 2\) where t is the time. If the particle starts out with a velocity \(u \quad \frac{2}{m} \quad i;\) at \{ = 0 , then the velocity at the end of 2 second is
Text Solution
Verified by ExpertsThe correct answer is:
B
\(v - u + \int \alpha t \, dt - u + \int (3t^2 + 2t + 2) \, dt\)
\(-u + \frac{3t^1}{3} + \frac{2t^1}{2} + 2t - u + t^3 + t^2 + 2t\)
\(2 + 8 + 4 + 4 \quad 18 \text{ m/s}\) (As t = 2 sec )
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