A particle starts from rest, accelerates at 2 m / s 2 for 10 s and then goes for constant speed for 30 s and then decelerates at 4 m / s 2 till it stops. What is the distance travelled by it
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Velocity acquired by body in 10 sec
\(v = 0 + 2 \times 10 = 20 \text{ m/s}\)
and distance travelled by it in 10 sec
\(s_1 = -\frac{1}{2} \times 2 \times (10)^2 = -100 \ m\)
then it moves with constant velocity (20 m/s ) for 30 sec
\(S_{2} \quad 20 \times 30 \quad 600 \ m\)
After that due to retardation \((4\,\mathrm{m/s}^2)\) it stops
\(s_3 - \frac{v^2}{2a} - \frac{(20)^2}{2 \times 4} - 50 m\)
Total distance travelled \(S_1 + S_2 + S_3 = 750\, m\)
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