A car, starting from rest, accelerates at the rate f through a distance S , then continues at constant speed for time t and then decelerates at the rate 
to come to rest. If the total distance traversed is 15 S , then
Text Solution
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Let car starts from point A from rest and moves up to point B with acceleration f
Velocity of car at point B , 
Car moves distance BC with this constant velocity in time t
......(i) [As 
]
So the velocity of car at point C also will be 
and finally car stops after covering distance y .
Distance CD ⇒ ⇒ 
....(ii)
So, the total distance AD = 
=15 S (given)
⇒ ⇒ 
⇒ ⇒ 
Substituting the value of x in equation (i) we get
⇒ ⇒ 
⇒ ⇒ 
⇒ ⇒ 
.
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