A body falling for 2 seconds covers a distance 5 equal to t…

Physics Motion in a Straight Line Motion Under Gravity Single Correct MCQ

Published on: September 11, 2026

A body falling for 2 seconds covers a distance 5 equal to that covered in next second. Taking g = 10 m/s^{2}, 5 =

30 m

10 m

60 m

20 m

Text Solution

Verified by Experts

The correct answer is:

If u is the initial velocity then distance covered by it in 2 sec

\(5 - uk + \frac{1}{2} \alpha^{i} - u \backslash 2 + \frac{1}{2} \backslash 10 \times 4 - 2u + 20\) …(i)

Now distance covered by it in 3 ^rd sec

\(S_{m} = -u + \frac{g}{2} (2 > 3 - 1) 10 - u + 25\) …(ii)

From(i) and (ii), \(2v + 20 = v + 25 \to v = 5\)

\(\mathrm{H - O - H}\) \(5\;2 \times 5 + 20\;30\;m\)

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