D

Step 1: Analyze the motion of the three particles:
- Particle A is thrown upwards, it will first decelerate due to gravity, stop at its highest point, and then accelerate downwards. It will hit the ground with a lower speed than it was initially thrown with due to the upward motion followed by fall.
- Particle B is thrown downwards; it will accelerate downwards throughout and hit the ground with the highest speed.
- Particle C is thrown horizontally; it will experience vertical acceleration due to gravity but its horizontal speed remains constant, resulting in a speed lower than B but higher than A when it impacts the ground.

Step 2: Using conservation of energy and kinematics, we can analyze the final speeds:
- Let the initial speed of each particle be \( v \). Particle B would have the maximum speed at impact, followed by C, and then A having the least.

Hence, the correct order of speeds at ground impact is: \( V_B > V_C > V_A \), confirming option D is correct.