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CGP EDU Academic Team
Published on: September 12, 2026
For any two vectors \vec{A} and \vec{B} , if \(\vec{A} \cdot \vec{B} = |\vec{A} \times \vec{B}|\) the magnitude of \vec{C} = \vec{A} + \vec{B} is equal to
Text Solution
Verified by ExpertsThe correct answer is:
D
\(AB \cos \theta = AB \sin \theta\) ⇒ ⇒ \(\tan \theta = 1\) ∴ ∴ \(\theta = 45^\circ\)
\(\left|\vec{C}\right| = \sqrt{A^{2} + B^{2} + 2AB \cos 45^{\circ}} = \sqrt{A^{2} + B^{2} + \sqrt{2} AB}\)
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