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CGP EDU Academic Team
Published on: September 12, 2026
The acceleration \(\left| a \right|\) in m/s^{2} of a particle is given by a = 3t^{2} + 2t + 2 where t is the time. If the particle starts out with a velocity u = 2 \ m/s at t = 0 , then the velocity at the end of 2 second is
Text Solution
Verified by ExpertsThe correct answer is:
B
\(v = u + \int adt = u + \int (3t^{2} + 2t + 2) dt\)
\(= u + \frac{3t^{3}}{3} + \frac{2t^{2}}{2} + 2t = u + t^{3} + t^{2} + 2t\)
\(= 2 + 8 + 4 + 4 = 18 \, m/s\) (As t = 2 sec )
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