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CGP EDU Academic Team
Published on: September 12, 2026
The relation \(3t = \sqrt{3x - 6}\) describes the displacement of a particle in one direction where X is in metres and t in sec. The displacement, when velocity is zero, is
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Verified by ExpertsThe correct answer is:
D
\(3t = \sqrt{3x - 6} \Rightarrow 3x = (3t)^2 + 6\)
\(\Rightarrow \mathbf{X} = 3t^{2} - 12t + 12\)
\(\mathbf{v} = \frac{dx}{dt} = 6t - 12\) , for v = 0, t = 2 sec
\(x = 3(2)^2 - 12 \times 2 + 12 = 0\)
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