A particle starts from rest, accelerates at 2 m / s 2 for 10 s and then goes for constant speed for 30 s and then decelerates at 4 m / s 2 till it stops. What is the distance travelled by it
Text Solution
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Velocity acquired by body in 10 sec
\(v = 0 + 2 \times 10 = 20\,m/s\)
and distance travelled by it in 10 sec
\(S_1 = \frac{1}{2} \times 2 \times (10)^2 = 100 \, m\)
then it moves with constant velocity (20 m/s ) for 30 sec
\(S_{2} = 20 \times 30 = 600 \ m^{2}\)
After that due to retardation \(\left(4\,m/s^{2}\right)\) it stops
\(S_3 = \frac{v^2}{2a} = \frac{(20)^2}{2 \times 4} = 50\, m\)
Total distance travelled S_{1} + S_{2} + S_{3} = 750 m
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