A body is released from the top of a tower of height h . It…

Physics Motion in a Straight Line Motion Under Gravity Single Correct MCQ

Published on: September 12, 2026

A body is released from the top of a tower of height h . It takes t sec to reach the ground. Where will be the ball after time t/2 sec

At h/2 from the ground

At h/4 from the ground

Depends upon mass and volume of the body

At 3h/4 from the ground

Text Solution

Verified by Experts

The correct answer is:

Let the body after time t/2 be at x from the top, then

\(x = \frac{1}{2} g t^{2} = \frac{1}{4} g t^{2} = \frac{1}{8} g t^{2}\) …(i)

\(h = \frac{1}{2} g t^{2}\) …(ii)

Eliminate t from (i) and (ii), we get \(x = \frac{h}{4}\)

Height of the body from the ground \(= h - \frac{h}{4} = \frac{3h}{4}\)

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