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CGP EDU Academic Team
Published on: September 12, 2026
A particle is dropped under gravity from rest from a height h (g = 9.8 m/sec^{2}) and it travels a distance 9h / 25 in the last second, the height h is
Text Solution
Verified by ExpertsThe correct answer is:
B
Let h distance is covered in n sec
\(\Rightarrow h = \frac{1}{2} g n^{2}\) …(i)
Distance covered in n^{th} sec \(= \frac{1}{2} g (2n - 1)\)
\(\Rightarrow \frac{9h}{25} = \frac{g}{2} (2n - 1)\) …(ii)
From (i) and (ii), \(h = 122.5 \, m\)
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