A ball is released from the top of a tower of height h meters. It takes T seconds to reach the ground. What is the position of the ball in T /3 seconds
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\(\boxed{} \quad h = ut + \frac{1}{2}gt^{2}\) \(\Rightarrow h = \frac{1}{2} g T^{2}\)
$h_2$ $\quad$ $h_2'$ $\quad$ $t = T/3$ $\quad$ $h_2 - h_2'$
After \(\frac{T}{3}\) seconds, the position of ball,
\(h' = 0 + \frac{1}{2} g \left( \frac{T}{3} \right)^2 = \frac{1}{2} \times \frac{g}{9} \times T^2\)
\(h' = \frac{1}{2} \times g \times T^{2}\) \(= \frac{h}{g m}\) from top
∴ ∴ Position of ball from ground \(= h - \frac{h}{9} = \frac{8h}{9} m.\)
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