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CGP EDU Academic Team
Published on: September 12, 2026
An aircraft executes a horizontal loop with a speed of 150 m / s with its, wings banked at an angle of 12^\circ . The radius of the loop is \(\left(g = 10 \, m/s^{2}\right)\)
Text Solution
Verified by ExpertsThe correct answer is:
A
The angle of banking, \(\tan \theta = \frac{v^{2}}{rg}\)
⇒ ⇒ \(\tan 12^\circ = \frac{(150)^2}{r \times 10}\) ⇒ ⇒ \(r = 10.6 \times 10^{3} m = 10.6 km\)
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