Published by:
CGP EDU Academic Team
Published on: September 13, 2026
An aeroplane moving horizontally with a speed of 720 km/h drops a food pocket, while flying at a height of 396.9 m . the time taken by a food pocket to reach the ground and its horizontal range is (Take g = 9.8 m/sec 2 )
Text Solution
Verified by ExpertsThe correct answer is:
D
\(t = \sqrt{\frac{2h}{g}} = \sqrt{\frac{2 \times 396.9}{9.8}} \simeq 9 \text{ sec}\) and \(u = 720 \text{ km/hr} = 200 \text{ m/s}\)
∴ ∴ \(R = u \times t = 200 \times 9 = 1800\,m\)
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