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CGP EDU Academic Team
Published on: September 12, 2026
The range of a particle when launched at an angle of 15^\circ with the horizontal is 1.5 km. What is the range of the projectile when launched at an angle of 45^\circ to the horizontal
Text Solution
Verified by ExpertsThe correct answer is:
B
\(R_{15^\circ} = \frac{u^2 \sin(2 \times 15^\circ)}{g}\) \(= \frac{u^{2}}{2g} = 1.5\,km\)
\(R_{45^\circ} = \frac{u^2 \sin(2 \times 45^\circ)}{g} = \frac{u^2}{g} = 1.5 \times 2 = 3\, km\)
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