A 60 kg body is pushed with just enough force to start it moving across a floor and the same force continues to act afterwards. The coefficient of static friction and sliding friction are 0.5 and 0.4 respectively. The acceleration of the body is
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Limiting friction $= \mu_{s} R = \mu_{s} mg = 0.5 \times 60 \times 10 = 300 \text{ N}$
Kinetic friction $= \mu_k R = \mu_k mg = 0.4 \times 60 \times 10 = 240 \text{ N}$
Force applied on the body F = 300N and if the body is moving then, Net accelerating force = Applied force - Kinetic friction
$\Rightarrow ma = 300 - 240 = 60 \therefore a = \frac{60}{60} = 1 \mathrm{m/s^2}$
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