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CGP EDU Academic Team
Published on: September 12, 2026
Two springs have their force constant as k 1 and $k_{2}(k_{1} > k_{2})$ . When they are stretched by the same force
Text Solution
Verified by ExpertsThe correct answer is:
C
$W = \frac{F^2}{2k}$
If both springs are stretched by same force then $W \propto \frac{1}{k}$
As $k_{1} > k_{2}$ therefore $W_1 < W_2$
i.e. more work is done in case of second spring.
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