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CGP EDU Academic Team
Published on: September 12, 2026
Two bodies of different masses $n_1$ and $n_2$ have equal momenta. Their kinetic energies $E_1$ and $E_2$ are in the ratio
Text Solution
Verified by ExpertsThe correct answer is:
C
$\mathrm{E} = \frac{\mathrm{p}^2}{2\mathrm{m}}$ if bodies possess equal linear momenta then $\mathbf{E} \propto \frac{1}{m} \text{ i.e. } \frac{E_1}{E_2} = \frac{m_2}{m_1}$
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