Two identical blocks A and B, each of mass 'm' resting on smooth floor are connected by a light spring of natural length L and spring constant K, with the spring at its natural length. A third identical block 'C' (mass m) moving with a speed v along the line joining A and B collides with A. the maximum compression in the spring is
Text Solution
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Initial momentum of the system (block C) = mv
After striking with A, the block C comes to rest and now both block A and B moves with velocity V,
when compression in spring is maximum.
By the law of conservation of linear momentum
mv = (m + m) V ⇒ ⇒ 
By the law of conservation of energy
K.E. of block C = K.E. of system + P.E. of system
⇒ ⇒ 
⇒ ⇒ 
⇒ ⇒ 
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