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CGP EDU Academic Team
Published on: September 12, 2026
A bomb of mass 3.0 Kg explodes in air into two pieces of masses 2.0 kg and 1.0 kg. The smaller mass goes at a speed of 80 m/s. The total energy imparted to the two fragments is
Text Solution
Verified by ExpertsThe correct answer is:
D
Both fragments will possess the equal linear momentum
$m_1 v_1 = m_2 v_2$ ⇒ ⇒ $1 \times 80 = 2 \times v_2$ ⇒ ⇒ $v_{2} = 40 \, m/s$
∴ ∴ Total energy of system $= \frac{1}{2} m_1 v_1^2 + \frac{1}{2} m_2 v_2^2$
= $\frac{1}{2} \times 1 \times (80)^2 + \frac{1}{2} \times 2 \times (40)^2$
= 4800 J = 4.8 kJ
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