A quarter horse power motor runs at a speed of 600 r.p.m. Assuming 40% efficiency the work done by the motor in one rotation will be
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Motor makes 600 revolution per minute
∴ ∴ n = $600 \frac{\text{revolution}}{\text{minute}} = 10 \frac{\text{rev}}{\text{sec}}$
∴ ∴ Time required for one revolution $\frac{1}{10}$ sec
Energy required for one revolution = power × time
= $\frac{1}{4} \times 746 \times \frac{1}{10} = \frac{746}{40} J$
But work done = 40% of input
$= 40\% \times \frac{746}{40} = \frac{40}{100} \times \frac{746}{40} = 7.46 \text{ kJ}$
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