Published by:
CGP EDU Academic Team
Published on: September 12, 2026
A body of mass 2 kg collides with a wall with speed 100 m/s and rebounds with same speed. If the time of contact was 1/50 second, the force exerted on the wall is
Text Solution
Verified by ExpertsThe correct answer is:
B
$F = \frac{dp}{dt} = m \frac{dv}{dt} = \frac{m \times 2v}{1/50 \text{ s}}$ = $\frac{2 \times 2 \times 100}{\frac{1}{50}} = 2 \times 10^{4} \, \mathrm{N}$
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