A neutron having mass of $1.67 \times 10^{-27} \mathrm{kg}$…

Physics Work, Energy, Power and Collision Perfectly Inelastic Collision Single Correct MCQ

Published on: September 13, 2026

A neutron having mass of $1.67 \times 10^{-27} \mathrm{kg}$ and moving at $10^{8} \mathrm{m}/\mathrm{s}$ collides with a deutron at rest and sticks to it. If the mass of the deutron is $3.34 \times 10^{-27} \mathrm{kg}$ then the speed of the combination is

$2.56 \times 10^{3} \mathrm{m/s}$

$2.98 \times 10^{5} \mathrm{m} / \mathrm{s}$

$3.33 \times 10^{7} \mathrm{m} / \mathrm{s}$

$5.01 \times 10^{9} \mathrm{m/s}$

Text Solution

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The correct answer is:

According to law of conservation of momentum.

Momentum of neutron = Momentum of combination

⇒ ⇒ $1.67 \times 10^{-27} \times 10^{8} = (1.67 \times 10^{-27} + 3.34 \times 10^{-27}) v$

∴ ∴ $v = 3.33 \times 10^{7} \mathrm{m/s}$

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