An open knife edge of mass 'm' is dropped from a height 'h'…

Physics Work, Energy, Power and Collision Mix Single Correct MCQ

Published on: September 12, 2026

An open knife edge of mass 'm' is dropped from a height 'h' on a wooden floor. If the blade penetrates upto the depth 'd' into the wood, the average resistance offered by the wood to the knife edge is

$mg\left(1-\frac{h}{d}\right)$

$mg\left(1+\frac{h}{d}\right)$

$mg\left(1+\frac{h}{d}\right)^2$

Text Solution

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The correct answer is:

Let the blade stops at depth d into the wood.

$v^{2} = u^{2} + 2 a s$

⇒ ⇒ $0 = \left(\sqrt{2gh}\right)^2 + 2(g - a)d$

by solving $a=\left(1+\frac{h}{d}\right)^g$

So the resistance offered by the wood $= mg \left( 1 + \frac{h}{d} \right)$

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